MATH SOLVE

3 months ago

Q:
# Suzy likes to mix and match her 3 necklaces, 2 bracelets, and 6 hats. The colors are listed in the table. On Monday, she randomly picks a bracelet, a necklace, and a hat. What is the probability of Suzy choosing a red bracelet and silver hat? NECKLACE COLORS: RED ,GREEN ,GOLD BRACELET COLORS: RED AND BLACK HAT COLORS: SILVER, YELLOW, GREEN, GOLD, BLACK, AND WHITE A. one-half B. one-fourth C. start fraction 1 over 6 end fraction D. start fraction 1 over 12 end fraction

Accepted Solution

A:

Answer: Option D. 1/12

We have:

3 Necklaces (red, green, and gold)

2 Bracelets (red and black)

6 hats (silver, yellow, green, gold, black, and white)

The number total of combinations is:

C=3x2x6→C=36 possible combinations

What is the probability of Suzy choosing a red bracelet and silver hat?

Possible combinations with a red bracelet and silver hat:

C1=1 (red bracelet) x 1 (silver hat) x 3 (necklaces: red, green, and gold)

C1=3 possible combinations with a red bracelet and silver hat

Probability of Suzy choosing a red bracelet and silver hat: P=C1/C

P=3/36

Simplifying the fraction dividing the numerator and the denominator by 3:

P=(3/3) / (36/3)

P=1/12

Answer: The probability of Suzy choosing a red bracelet and silver hat is 1/12

We have:

3 Necklaces (red, green, and gold)

2 Bracelets (red and black)

6 hats (silver, yellow, green, gold, black, and white)

The number total of combinations is:

C=3x2x6→C=36 possible combinations

What is the probability of Suzy choosing a red bracelet and silver hat?

Possible combinations with a red bracelet and silver hat:

C1=1 (red bracelet) x 1 (silver hat) x 3 (necklaces: red, green, and gold)

C1=3 possible combinations with a red bracelet and silver hat

Probability of Suzy choosing a red bracelet and silver hat: P=C1/C

P=3/36

Simplifying the fraction dividing the numerator and the denominator by 3:

P=(3/3) / (36/3)

P=1/12

Answer: The probability of Suzy choosing a red bracelet and silver hat is 1/12