MATH SOLVE

3 months ago

Q:
# During halftime of a football game a slingshot launches T-shirts at the crowd a T-shirt is launched from a height of 6 feet with an initial upward velocity of 72 ft./s the T-shirt is cot 45 feet above the field how long will it take the T-shirt to reach the maximum height what is the maximum height what is the range of the function that models the height of the T-shirt overtime

Accepted Solution

A:

Answer:2.25 seconds87 feet[6, 87]Step-by-step explanation:The height of a projectile is:h(t) = -16t² + vt + swhere v is the initial vertical velocity and s is the initial height.Here, v = 72 and s = 6.h(t) = -16t² + 72t + 6This is a downwards parabola. The maximum is at the vertex.t = -b / (2a)t = -72 / (2×-16)t = 2.25h(2.25) = 87It takes 2.25 seconds to reach the maximum height of 87 feet.The range is from the lowest height (6 feet) to the maximum height (87 feet). In interval notation:[6, 87]